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8z^2-13z=5
We move all terms to the left:
8z^2-13z-(5)=0
a = 8; b = -13; c = -5;
Δ = b2-4ac
Δ = -132-4·8·(-5)
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{329}}{2*8}=\frac{13-\sqrt{329}}{16} $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{329}}{2*8}=\frac{13+\sqrt{329}}{16} $
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